Answers: Amines Worksheet
Section A: Objective Questions
IUPAC Name: N-Methylmethanamine
Tertiary amines do not react with Hinsberg’s reagent because they do not have a replaceable hydrogen atom on the nitrogen.
Isomerism:
(a) Functional isomerism
(b) Position isomerismOrder of Basicity:
Structure of N-ethylethanamine:
Section B: Short Answer Questions
Conversions:
(a) Nitrobenzene to Aniline:(b) Aniline to p-Bromoaniline:
Reaction of Ethylamine with Benzoyl Chloride (Hinsberg Test):
- Ethylamine reacts with benzoyl chloride to form N-ethylbenzamide.
- Mechanism: The lone pair of electrons on the nitrogen of ethylamine attacks the carbonyl carbon of benzoyl chloride, displacing the chlorine atom.
Aniline is less basic than methylamine because:
- The lone pair of electrons on nitrogen in aniline is delocalized into the benzene ring, reducing its availability for protonation.
Section C: Long Answer Questions
Hoffmann Bromamide Reaction:
- Importance: Used to prepare primary amines from amides, with the loss of one carbon atom from the chain.
(a) Distinguish:
Aniline vs. N-Methylaniline:
Add bromine water: Aniline gives a white precipitate (2,4,6-tribromoaniline), while N-methylaniline does not.Primary amine vs. Tertiary amine:
Hinsberg Test: Primary amines react to form soluble sulfonamide, while tertiary amines do not react.
(b) Coupling Reaction with Diazonium Salts:
- Reaction:
- Diazonium salts react with phenols or aromatic amines to form azo compounds, used in dye synthesis.
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