Monday 7 October 2024

SN1 AND SN2 20 MCQS

 Here are 20 MCQs without the answers:

  1. Which of the following alkyl halides undergoes SN1 reaction most readily?

    • a) Methyl chloride
    • b) Ethyl chloride
    • c) Isopropyl chloride
    • d) Tert-butyl chloride
  2. What is the rate-determining step in the SN1 mechanism?

    • a) Nucleophilic attack
    • b) Formation of carbocation
    • c) Departure of leaving group and nucleophilic attack together
    • d) Rearrangement of the substrate
  3. In SN2 reactions, which of the following is true about stereochemistry?

    • a) Retention of configuration
    • b) Racemization
    • c) Inversion of configuration
    • d) No effect on stereochemistry
  4. Which type of solvent favors an SN2 reaction?

    • a) Polar protic solvent
    • b) Non-polar solvent
    • c) Polar aprotic solvent
    • d) Amphiprotic solvent
  5. The order of reactivity of alkyl halides in SN2 reactions is:

    • a) Tertiary > Secondary > Primary
    • b) Primary > Secondary > Tertiary
    • c) Secondary > Primary > Tertiary
    • d) Tertiary > Primary > Secondary
  6. Why do tertiary alkyl halides favor the SN1 mechanism?

    • a) Low steric hindrance
    • b) High carbocation stability
    • c) Fast nucleophilic attack
    • d) Poor leaving group stability
  7. Which of the following nucleophiles will most likely favor an SN2 mechanism?

    • a) H₂O
    • b) CH₃O⁻
    • c) NH₃
    • d) ROH
  8. In which of the following cases is racemization observed?

    • a) SN1 reaction of chiral alkyl halide
    • b) SN2 reaction of chiral alkyl halide
    • c) Free radical substitution
    • d) E2 reaction
  9. Which of the following alkyl halides is most reactive in an SN2 mechanism?

    • a) Methyl halides
    • b) Primary alkyl halides
    • c) Secondary alkyl halides
    • d) Tertiary alkyl halides
  10. The slowest step in an SN1 reaction is:

    • a) Attack of nucleophile
    • b) Formation of carbocation
    • c) Rearrangement of the carbocation
    • d) Departure of leaving group
  11. Which of the following substrates is most reactive in an SN1 reaction?

    • a) Vinyl chloride
    • b) Chlorobenzene
    • c) Methyl chloride
    • d) Benzyl chloride
  12. Which mechanism involves a concerted one-step process?

    • a) SN2 mechanism
    • b) SN1 mechanism
    • c) Free radical mechanism
    • d) E1 mechanism
  13. Which of the following is a good leaving group for SN2 reactions?

    • a) Cl⁻
    • b) OH⁻
    • c) H⁻
    • d) NH₂⁻
  14. Which of the following is the least likely intermediate in an SN1 reaction?

    • a) Primary carbocation
    • b) Tertiary carbocation
    • c) Benzyl carbocation
    • d) Secondary carbocation
  15. What is the slowest step in an SN1 reaction mechanism?

    • a) Attack of nucleophile
    • b) Leaving group departure
    • c) Slow formation of a carbocation
    • d) Rearrangement of the substrate
  16. Which of the following will undergo an SN2 reaction fastest?

    • a) Secondary alkyl halide
    • b) Tertiary alkyl halide
    • c) Methyl halide
    • d) Vinyl halide
  17. What type of rate law does an SN2 reaction follow?

    • a) Zero order
    • b) Unimolecular
    • c) Bimolecular
    • d) First order
  18. Which of the following favors SN2 reactions?

    • a) Polar protic solvents
    • b) Polar aprotic solvents
    • c) Non-polar solvents
    • d) Weak nucleophiles
  19. Which of the following is the best leaving group for an SN1 reaction?

    • a) Fluoride ion (F⁻)
    • b) Bromide ion (Br⁻)
    • c) Chloride ion (Cl⁻)
    • d) Iodide ion (I⁻)
  20. What is the first step in an SN1 reaction?

    • a) Nucleophile attacks the carbon
    • b) Formation of carbocation
    • c) Formation of bond with nucleophile
    • d) Leaving group departure

These MCQs will help in testing knowledge of SN1 and SN2 reactions



ANSWERS


Here are the answers with reasons:

  1. d) Tert-butyl chloride
    Reason: Tertiary alkyl halides form the most stable carbocations, favoring the SN1 mechanism.

  2. b) Formation of carbocation
    Reason: The formation of a carbocation is the slowest step in the SN1 mechanism, making it the rate-determining step.

  3. c) Inversion of configuration
    Reason: SN2 reactions involve backside attack, leading to inversion of configuration (Walden inversion).

  4. c) Polar aprotic solvent
    Reason: Polar aprotic solvents do not solvate the nucleophile, making it more reactive for SN2 reactions.

  5. b) Primary > Secondary > Tertiary
    Reason: SN2 reactions are hindered by steric factors, so less substituted alkyl halides react faster.

  6. b) High carbocation stability
    Reason: Tertiary alkyl halides form stable carbocations, which is essential for the SN1 mechanism.

  7. b) CH₃O⁻
    Reason: Methoxide ion (CH₃O⁻) is a strong nucleophile, favoring the SN2 mechanism.

  8. a) SN1 reaction of chiral alkyl halide
    Reason: SN1 reactions involve a planar carbocation intermediate, leading to racemization.

  9. a) Methyl halides
    Reason: Methyl halides have the least steric hindrance, making them highly reactive in SN2 reactions.

  10. b) Formation of carbocation
    Reason: Carbocation formation is the slowest, rate-determining step in the SN1 mechanism.

  11. d) Benzyl chloride
    Reason: Benzyl chloride forms a highly stabilized benzyl carbocation, making it very reactive in SN1.

  12. a) SN2 mechanism
    Reason: SN2 is a concerted one-step process, involving simultaneous nucleophilic attack and leaving group departure.

  13. a) Cl⁻
    Reason: Chloride ion is a good leaving group, making it suitable for SN2 reactions.

  14. a) Primary carbocation
    Reason: Primary carbocations are highly unstable, making them unlikely intermediates in SN1 reactions.

  15. c) Slow formation of a carbocation
    Reason: The slowest step in SN1 is the departure of the leaving group and the formation of the carbocation.

  16. c) Methyl halide
    Reason: Methyl halides have no steric hindrance, making them most reactive in SN2 reactions.

  17. c) Bimolecular
    Reason: SN2 reactions depend on the concentrations of both the nucleophile and the substrate, making it bimolecular.

  18. b) Polar aprotic solvents
    Reason: Polar aprotic solvents enhance nucleophilicity without stabilizing the nucleophile, favoring SN2 reactions.

  19. d) Iodide ion (I⁻)
    Reason: Iodide ion is the best leaving group because it is large and easily dissociates.

  20. b) Formation of carbocation
    Reason: The first step in SN1 is the departure of the leaving group, leading to carbocation formation.

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