Class 12 Chemistry chapter “Solutions”, designed based on previous year questions (PYQs) from CBSE board exams. Each question includes a concise answer and covers important concepts like concentration terms, Raoult’s Law, colligative properties, abnormal molar mass, and more.
📘 Chapter: Solutions – Class 12
🧪 PYQ-Based Questions with Answers
1. Define mole fraction. What is the sum of mole fractions of all components in a solution?
Answer:
Mole fraction is the ratio of moles of one component to the total moles of all components in the solution.
2. State Henry’s Law and mention its application.
Answer:
Henry’s Law: The solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid.
3. What is the effect of temperature on solubility of gases in liquids?
Answer:
The solubility of gases in liquids decreases with increase in temperature because dissolution of gas is an exothermic process.
4. Define ideal and non-ideal solutions. Give one example of each.
Answer:
- Ideal solution: Obeys Raoult’s law at all concentrations (e.g., benzene + toluene).
- Non-ideal solution: Shows deviation from Raoult’s law (e.g., acetone + chloroform).
5. State Raoult’s Law for a solution of volatile liquids.
Answer:
Raoult’s Law: The partial vapor pressure of each component in a solution is directly proportional to its mole fraction.
6. A solution contains 30 g of urea (M = 60 g/mol) in 246 g of water. Calculate the mole fraction of urea.
Given:
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Mass of urea =
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Molar mass of urea (M) =
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Mass of water =
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Molar mass of water =
Step 1: Calculate moles of urea
Step 2: Calculate moles of water
Step 3: Calculate mole fraction of urea
Mole fraction of urea:
✅ Final Answer:
The mole fraction of urea is 0.035 (approx.)
7. What is meant by abnormal molar mass? How is it caused?
Answer:
Abnormal molar mass is the molar mass calculated using colligative properties that differs from the actual molar mass due to association or dissociation of solute particles in solution.
8. A solution of glucose (C₆H₁₂O₆) in water is 1 molal. What is the freezing point of the solution? (Kf for water = 1.86 K kg/mol).
Given:
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Molality () =
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Solute = glucose () → a non-electrolyte (does not dissociate, so )
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for water =
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Normal freezing point of water =
Step 1: Formula for depression in freezing point
Step 2: Substitute values
Step 3: Calculate new freezing point
✅ Final Answer:
The freezing point of the solution is –1.86 °C.
9. What is van’t Hoff factor (i)? What is its value for glucose and NaCl in aqueous solution?
Case 1: Glucose (C₆H₁₂O₆)
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Glucose is a non-electrolyte.
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It does not ionize in water.
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Each molecule stays intact.
Case 2: Sodium Chloride (NaCl)
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NaCl is an electrolyte.
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It dissociates completely in aqueous solution:
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1 formula unit of NaCl → 2 particles.
(Note: In practice, due to incomplete dissociation and ion pairing, the experimental value may be slightly less than 2.)
✅ Final Answer:
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For glucose:
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For NaCl:
10. What are azeotropes? Give one example each of minimum and maximum boiling azeotrope.
Answer:
Azeotropes are mixtures that boil at a constant temperature without change in composition.
- Minimum boiling: Ethanol + water
- Maximum boiling: HNO₃ + H₂O
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