Friday, 28 November 2025

 Below are 10 most repeated / high-probability board exam questions from Class 12 Chemistry – Chapter: Solutions, each with detailed answers.

(These are based on the latest NCERT pattern, past-year CBSE papers & sample papers.)



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⭐ 10 Most Repeated Board Questions – Solutions (Class 12 Chemistry)


With Detailed Answers



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1. Define molality and molarity. Why is molality preferred over molarity?


Answer:


Molarity (M):

Number of moles of solute dissolved in 1 litre of solution.



M = \frac{\text{moles of solute}}{\text{volume of solution (L)}}


Molality (m):

Number of moles of solute dissolved in 1 kg of solvent.



m = \frac{\text{moles of solute}}{\text{mass of solvent (kg)}}


Why molality is preferred?


Molality is temperature independent, because it depends on mass (kg).

Molarity changes with temperature because volume changes with temperature.



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2. State Raoult’s Law for a solution of volatile liquids.


Answer:


For a solution containing two volatile components A and B:


p_A = x_A p_A^\circ,\quad p_B = x_B p_B^\circ


Total vapour pressure:


p = p_A + p_B


Where:


 = vapour pressures of pure components


 = mole fractions



Meaning:


Each component contributes to total vapour pressure in proportion to its mole fraction.



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3. What are ideal and non-ideal solutions? Give examples.


Answer:


Ideal solution


A solution that follows Raoult’s law at all compositions and temperatures.


Characteristics:


No enthalpy change: 


No volume change: 


Intermolecular forces A–A, B–B, A–B are equal.



Examples: benzene + toluene, n-hexane + n-heptane


Non-ideal solution


A solution that does NOT follow Raoult’s law and shows deviation.



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4. Explain positive and negative deviations from Raoult’s Law. Give two examples.


Answer:


Positive deviation


A–B attraction < A–A or B–B


High vapour pressure


Endothermic mixing

Examples: Ethanol + acetone, ethanol + water



Negative deviation


A–B attraction > A–A or B–B


Low vapour pressure


Exothermic mixing

Examples: Acetone + chloroform, HNO₃ + water




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5. Define azeotropes. Write the types with examples.


Answer:


Azeotropes are constant-boiling mixtures whose composition cannot be changed by distillation.


Types:


1. Minimum boiling azeotrope (positive deviation)

Example: Ethanol–water (95% ethanol)



2. Maximum boiling azeotrope (negative deviation)

Example: HCl–water (20% HCl)





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6. What is Henry’s Law? Write its formula and application.


Answer:


Henry's law states:


"The solubility of a gas in a liquid is directly proportional to the partial pressure of the gas."


p = k_H x


Where:


 = pressure


 = mole fraction of gas


 = Henry’s law constant



Applications:


Carbonated drinks


Deep-sea diving gases


Purification of water




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7. What is colligative property? Name four colligative properties.


Answer:


Colligative properties depend only on number of solute particles, not on their nature.


Four colligative properties:


1. Relative lowering of vapour pressure



2. Elevation in boiling point



3. Depression in freezing point



4. Osmotic pressure





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8. Derive the relation between elevation in boiling point and molality.


Answer:


Elevation in boiling point:


\Delta T_b = K_b m


Where:


 = molal elevation constant


 = molality



Derivation idea:

Raoult’s law → lowering of vapour pressure → Clausius–Clapeyron equation → relation between ΔTb and molality.


Final formula:


\Delta T_b = K_b m



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9. Write the Van’t Hoff factor (i) and its significance.


Answer:


Van’t Hoff factor (i):


i = \frac{\text{observed colligative property}}{\text{normal colligative property}}


Significance:


Accounts for association (i < 1)


Accounts for dissociation (i > 1)



Example:


NaCl → Na⁺ + Cl⁻ → i ≈ 2


CH₃COOH (association in benzene) → i < 1




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10. Define osmotic pressure. Derive the formula used to calculate molar mass.


Answer:


Osmotic pressure (π):


\pi = MRT


Where:


 = molarity of solution


 = gas constant


 = temperature in Kelvin



Relation for molar mass:


\pi = \frac{n}{V} RT = \frac{w}{M_2} \cdot \frac{RT}{V}


So,


M_2 = \frac{wRT}{\pi V}


This formula is used to determine molar mass of solutes (especially polymers).



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If you want, I can also prepare:

📘 Top 20 very important numericals

📝 Full chapter mock test (40 marks)

📄 Board-exam style case-based questions for Solutions

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